bundy351 is right, basically the same as the cal-track, just building it myself.
tappet, the holes are 12mm and I'll use hightensile, that gives you a shear strength of about 7199kg, doubled because you have two shear faces, it's comes to roughly 14398kg's of force you have to apply before the bolt might shear of. That's not including the clamping force on the sides of the tubes, which now also has to be moved before the bolt shear strength comes into play. Breaking them becomes highly unlikely under these circumstances...
Disclaimer: I worked these things out very quickly, so there might be some errors in my findings...
10.9 = 1040mpa tensile
1mpa = 1n/mm**2
Pi * (r * r)
12mm = Pi * 36 = 113.14285714285714285714285714286mm**2
UTS = 1040 * 113.14285714285714285714285714286 = 117668.57142857142857142857142857n
shear strength = 0.6 * UTS (very rough estimation with some safty in there...)
0.6 * 117668.57142857142857142857142857n = 70601.142857142857142857142857143n
1 newton = 0.10197162129799997 kilogram-force
70601.142857142857142857142857143n * 0.10197162129799997 = 7199.313002634567 kilogram-force